document.write( "Question 582488: Can you please exlpain step by step how to solve 2/x-3 - 4/x+3 = 8/x^2-9 \n" ); document.write( "
Algebra.Com's Answer #372102 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! \n" ); document.write( "The third denominator is the difference of squares and can be factored to; \n" ); document.write( " \n" ); document.write( "Multiply each term by (x-3)(x+3) \n" ); document.write( "(x-3)(x+3)* \n" ); document.write( "Cancel the denominators and you have: \n" ); document.write( "2(x+3) - 4(x-3) = 8 \n" ); document.write( "2x + 6 - 4x + 12 = 8 \n" ); document.write( "2x - 4x + 18 = 8 \n" ); document.write( "-2x = 8 - 18 \n" ); document.write( "-2x = -10 \n" ); document.write( "x = +5 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this in the original problem for x = 5 \n" ); document.write( " |