document.write( "Question 582523: 1) I am a 2-digit number less than 90.
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document.write( "2) Three more than my value is an even number.
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document.write( "3) The sum of my digits is a multiple of 8. \n" );
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Algebra.Com's Answer #372081 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! 2) Three more than my value is an even number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is just a \"tricky\" way of saying \"I am an odd number.\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3) The sum of my digits is a multiple of 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since we have a 2-digit number, the digit sum must be either 8 or 16 (24 is too large). If it is 8, then we have 71, 53, 35, 17. If it is 16, we have 79 (97 is too large).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore all the possible numbers are 17, 35, 53, 71, and 79. \n" ); document.write( " |