document.write( "Question 582465: Give each zero and its multiplicity:\r
\n" ); document.write( "\n" ); document.write( "x(2-x)(x+3)^2\r
\n" ); document.write( "\n" ); document.write( "how do I go about finding these??
\n" ); document.write( "

Algebra.Com's Answer #372064 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
x(2-x)(x+3)^2 = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 0, 2-x=0, or (x+3)^2 = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 0, x = 2, or x = -3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The first two zeros of x = 0 and x = 2 are of multiplicity one.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The last zero x = -3 is of multiplicity two.
\n" ); document.write( "
\n" );