document.write( "Question 582406: how we will find that ph=-log[h+] if ph=7 \n" ); document.write( "
Algebra.Com's Answer #372042 by Earlsdon(6294)\"\" \"About 
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ph = -log[H+] Substitute ph = 7
\n" ); document.write( "7 = -log[H+] Divide both sides by -1.
\n" ); document.write( "-7 = log[H+] Now rewrite this in exponential form.
\n" ); document.write( "10^(-7) = [H+]
\n" ); document.write( "[H+] = 10^(-7) or [H+] = 0.0000001
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