document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=582271>Question 582271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a certain fraction, the numerator is 4 less than the denominator. If 2 is subtracted both to the numerator and the denominator, the resulting fraction is equal to 1/2. Find the original fraction in lowest terms........PLEASE HELP </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #372025 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=372025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the fraction be x/y\r<BR>\n" );
document.write( "\n" );
document.write( "x=y-4\r<BR>\n" );
document.write( "\n" );
document.write( "(x-2)/(y-2) =1/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "cross multiply\r<BR>\n" );
document.write( "\n" );
document.write( "2(x-2)= y-2<BR>\n" );
document.write( "2x-4 = y-2<BR>\n" );
document.write( "2x-y = -2+4<BR>\n" );
document.write( "2x-y = 2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the two equations are x-y = -4<BR>\n" );
document.write( "2x-y =2\r<BR>\n" );
document.write( "\n" );
document.write( "subtract the first equation from the second\r<BR>\n" );
document.write( "\n" );
document.write( "2x-y -(x-y) = 2-(-4)\r<BR>\n" );
document.write( "\n" );
document.write( "x= 6\r<BR>\n" );
document.write( "\n" );
document.write( "y =10\r<BR>\n" );
document.write( "\n" );
document.write( "The fraction is 6/10 = 3/5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );