document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6744>Question 6744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Even though I understand the foil process, we were asked a question like this;\r<BR>\n" );
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document.write( " I have the answer when solving for \"a\" which is 2, but how on earth did they get the answer.  HELP!  Can you I see the work on this type of problem. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3720 by </B><A HREF=/tutors/aboutme.mpl?userid=IA><B>IA(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=IA><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2a + 3b= 19<BR>\n" );
document.write( "5a - 2b= 0\r<BR>\n" );
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document.write( "4a+6b=38 (double first equation)<BR>\n" );
document.write( "15a-6b=0  (triple second equation)<BR>\n" );
document.write( " to cancel out the b add the equations togther. <BR>\n" );
document.write( "this gives 19a = 38. divide both sides by 19. a=2. <BR>\n" );
document.write( "then substitute 2 into the equation for a and use the same method to solve b.  </SPAN>\n" );
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