document.write( "Question 580965: The sum of two numbers is 27. The larger number is 3 more than the smaller number. What are the two numbers? \n" ); document.write( "
Algebra.Com's Answer #371966 by computergeek008(7)\"\" \"About 
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Let x be the larger number, and y be the smaller number.\r
\n" ); document.write( "\n" ); document.write( "The sum of two numbers is 27. So the equation would be:
\n" ); document.write( "\"x%2By=27\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The larger number is 3 more than the smaller number. So:\r
\n" ); document.write( "\n" ); document.write( "larger number = smaller number + 3\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"x+=+y+%2B+3\"\r
\n" ); document.write( "\n" ); document.write( "Now, we want to get rid of x and solve for y first. Since \"x=y%2B3\", we can substitute y+3 for x in the equation \"x%2By=27\".\r
\n" ); document.write( "\n" ); document.write( "Therefore:
\n" ); document.write( "(y + 3) + y = 27\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:
\n" ); document.write( "2y + 3 = 27\r
\n" ); document.write( "\n" ); document.write( "Subtract 3 on both sides:
\n" ); document.write( "2y = 24\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 2:
\n" ); document.write( "y = 12\r
\n" ); document.write( "\n" ); document.write( "So the smaller number is 12. The larger number is 3 more than the smaller number, so:\r
\n" ); document.write( "\n" ); document.write( "x = 12 + 3
\n" ); document.write( "x = 15\r
\n" ); document.write( "\n" ); document.write( "The 2 numbers are 12 and 15. Check:\r
\n" ); document.write( "\n" ); document.write( "12 + 15 = 27
\n" ); document.write( "which is correct.\r
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