document.write( "Question 580965: The sum of two numbers is 27. The larger number is 3 more than the smaller number. What are the two numbers? \n" ); document.write( "
Algebra.Com's Answer #371966 by computergeek008(7)![]() ![]() You can put this solution on YOUR website! Let x be the larger number, and y be the smaller number.\r \n" ); document.write( "\n" ); document.write( "The sum of two numbers is 27. So the equation would be: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The larger number is 3 more than the smaller number. So:\r \n" ); document.write( "\n" ); document.write( "larger number = smaller number + 3\r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, we want to get rid of x and solve for y first. Since \n" ); document.write( "\n" ); document.write( "Therefore: \n" ); document.write( "(y + 3) + y = 27\r \n" ); document.write( "\n" ); document.write( "Combine like terms: \n" ); document.write( "2y + 3 = 27\r \n" ); document.write( "\n" ); document.write( "Subtract 3 on both sides: \n" ); document.write( "2y = 24\r \n" ); document.write( "\n" ); document.write( "Divide both sides by 2: \n" ); document.write( "y = 12\r \n" ); document.write( "\n" ); document.write( "So the smaller number is 12. The larger number is 3 more than the smaller number, so:\r \n" ); document.write( "\n" ); document.write( "x = 12 + 3 \n" ); document.write( "x = 15\r \n" ); document.write( "\n" ); document.write( "The 2 numbers are 12 and 15. Check:\r \n" ); document.write( "\n" ); document.write( "12 + 15 = 27 \n" ); document.write( "which is correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |