document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=582010>Question 582010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help solve this problem....thanks.\r<BR>\n" );
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document.write( "George can cut and split a cord of firewood in 3 fewer hour(s) than Skylar can. When they work togethe it takes them 2 hr(s).How long would it take each of them to do the job alone?\r<BR>\n" );
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document.write( "George?<BR>\n" );
document.write( "Skylar?\r<BR>\n" );
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document.write( "Simplify answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371927 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371927\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of time it takes Skyler to do the job<BR>\n" );
document.write( "Then (x-3) = amount of time it takes George to do the job<BR>\n" );
document.write( "Skyler works at the rate of 1/x job per hour<BR>\n" );
document.write( "George works at the rate of 1/(x-3) job per hour<BR>\n" );
document.write( "Together they work at the rate of 1/2 of the job per hour<BR>\n" );
document.write( "sooooo:<BR>\n" );
document.write( "1/x +1/(x-3)=1/2  multiply each side by 2x(x-3)<BR>\n" );
document.write( "2(x-3)+2x=x(x-3) simplify<BR>\n" );
document.write( "2x-6+2x=x^2-3x  collect like terms<BR>\n" );
document.write( "4x-6=x^2-3x<BR>\n" );
document.write( "x^2-7x+6=0  quadratic in standard form and it can be factored<BR>\n" );
document.write( "(x-6)(x-1)=0<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x=1  Clearly x=1 does not work because George would have do do negative work to do the job in 3 hours fewer time, sooooo<BR>\n" );
document.write( "x=6 hours time time it takes Skyler to do the job<BR>\n" );
document.write( "x-3=6-3=3 hours time it takes George to do the job<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "1/6+1/3=1/2<BR>\n" );
document.write( "1/6 + 2/6=1/2<BR>\n" );
document.write( "1/2=1/2\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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