document.write( "Question 582048: how do i find the value of cotx if secxsinx= 2 \n" ); document.write( "
Algebra.Com's Answer #371923 by Edwin McCravy(20086)\"\" \"About 
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document.write( "cot(x) = \"cos%28x%29%2Fsin%28x%29\" = \"%281%2Fsec%28x%29%29%2Fsin%28x%29\" =\r\n" );
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document.write( "       [Multiply top and bottom by sec(x)]\r\n" );
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document.write( "= \"1%2F%28sec%28x%29sin%28x%29%29\" = \"1%2F2\"\r\n" );
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document.write( "Edwin
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