document.write( "Question 6739: sqrt(5x+6)-sqrt(3x-2)=2 solve for x. \r
\n" ); document.write( "\n" ); document.write( "please show all the steps involved. thanks!
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Algebra.Com's Answer #3719 by Earlsdon(6294)\"\" \"About 
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Solve:
\n" ); document.write( "\"sqrt%285x%2B6%29-sqrt%283x-2%29+=+2\" Add \"sqrt%283x-2%29\" to both sides.
\n" ); document.write( "\"sqrt%285x%2B6%29+=+2+%2B+sqrt%283x-2%29\" Square both sides.
\n" ); document.write( "\"%285x%2B6%29+=+4+%2B+4sqrt%283x-2%29+%2B+%283x-2%29\" Simplify.
\n" ); document.write( "\"5x%2B6+=+2+%2B+3x+%2B+4sqrt%283x-2%29\" Subtract 3x from both sides.
\n" ); document.write( "\"2x%2B6+=+2+%2B+4sqrt%283x-2%29\" Subtract 2 from both sides.
\n" ); document.write( "\"2x%2B4+=+4sqrt%283x-2%29\" Square both sides.
\n" ); document.write( "\"4x%5E2+%2B+16x+%2B+16+=+16%283x-2%29\" Simplify.
\n" ); document.write( "\"4x%5E2+%2B+16x+%2B+16+=+48x+-+32\" Subtract 48x from both sides.
\n" ); document.write( "\"4x%5E2+-+32x+%2B+16+=+-32\" Add 32 to both sides.
\n" ); document.write( "\"4x%5E2+-+32x+%2B+48+=+0\" Divide both sides by 4.
\n" ); document.write( "\"x%5E2+-+8x+%2B+12+=+0\" Solve by factoring.
\n" ); document.write( "\"%28x+-+2%29%28x+-+6%29+=+0\" Apply the zero product principle.\r
\n" ); document.write( "\n" ); document.write( "x - 2 = 0, x = 2 or
\n" ); document.write( "x - 6 = 0, x = 6
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