document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581939>Question 581939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me find the domain of the function 5(x+4)/x^2+x-12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371879 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint: You CANNOT divide by zero. So the denominator x^2+x-12 can't be zero.\r<BR>\n" );
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document.write( "If it were, then x^2+x-12 = 0. Solve this equation for x and those solutions will be the values of x that make the denominator zero. This means that you must exclude them from the domain.\r<BR>\n" );
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document.write( "So the domain will be the set of all real numbers except that x can't equal the solutions to the equation above. </SPAN>\n" );
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