document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581807>Question 581807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please show me how to solve this problem: the perimeter of a rectangle is 50m. if the width were doubled and the length were increased by 25m, the perimeter would be 112m. what are the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371873 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"the perimeter of a rectangle is 50m\" ___ 2L + 2W = 50 (A)\r<BR>\n" );
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document.write( "\"if the width were doubled and the length were increased by 25m, the perimeter would be 112m\"<BR>\n" );
document.write( "___ 2(L + 25) + 2(2W) = 112 ___ 2L + 50 + 4W = 112 (B)\r<BR>\n" );
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document.write( "subtracting equation A from equation B will eliminate L\r<BR>\n" );
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document.write( "find W, and then substitute back to find L </SPAN>\n" );
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