document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581929>Question 581929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you x so that x, x+2, and x+3 are consecutive terms of a geometric sequence and find the common ratio r of the sequence. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371871 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x, x+2, and x+3 are consecutive terms of a geometric sequence and find the common ratio r of the sequence.<BR>\n" );
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document.write( "Solve: (x+2)/x = (x+3)/(x+2)<BR>\n" );
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document.write( "x(x+3) = (x+2)^2<BR>\n" );
document.write( "x^2+3x = x^2+4x+4<BR>\n" );
document.write( "x = -4<BR>\n" );
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document.write( "Common ratio = -4<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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