document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581859>Question 581859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello there, I have a project due monday about graphing circles using my ti-83.<BR>\n" );
document.write( "there are four assingment and the 1st of four is to graph a few concetric circles with an origin of (0,0).<BR>\n" );
document.write( "I must write my equations in (x+h) squared + (y-K) squared = radius squared.<BR>\n" );
document.write( "but then I must solve for y<BR>\n" );
document.write( ". what i dont understand is how to solve for y  <BR>\n" );
document.write( "please give me an example on how to do this problem then i can do the rest on my own. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371831 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A circle with radius r, centered at point (h,k) has the equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Your circles, centered at (0,0) will have the equation<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=r%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "For a radius of 2, since <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E2=4 ALIGN=MIDDLE  ALT=\"2%5E2=4\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the equation would be<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=4 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Solving for y, you will get two functions, representing the top half of the circle, and the bottom half of the circle.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=4 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=4\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2=4-x%5E2 ALIGN=MIDDLE  ALT=\"y%5E2=4-x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Then for the top half<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=sqrt%284-x%5E2%29 ALIGN=MIDDLE  ALT=\"y=sqrt%284-x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and for the bottom half<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=-sqrt%284-x%5E2%29 ALIGN=MIDDLE  ALT=\"y=-sqrt%284-x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );