document.write( "Question 581781: The sum of the reciprocals of two numbers is 3/2, and the difference of their rciprocals is 5/12. what are the two numbers \n" ); document.write( "
Algebra.Com's Answer #371829 by ankor@dixie-net.com(22740)\"\" \"About 
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The sum of the reciprocals of two numbers is 3/2, and the difference of their reciprocals is 5/12.
\n" ); document.write( "what are the two numbers
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\n" ); document.write( "\"1%2Fa\" + \"1%2Fb\" = \"3%2F2\"
\n" ); document.write( "\"1%2Fa\" + \"1%2Fb\" = \"18%2F12\"
\n" ); document.write( "and
\n" ); document.write( "\"1%2Fa\" - \"1%2Fb\" = \"5%2F12\"
\n" ); document.write( "-------------------------adding eliminates b, find a
\n" ); document.write( "\"2%2Fa\" = \"23%2F12\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "23a = 2*12
\n" ); document.write( "23a = 24
\n" ); document.write( "a = \"24%2F23\"
\n" ); document.write( "Find b
\n" ); document.write( "\"23%2F24\" + \"1%2Fb\" = \"3%2F2\"
\n" ); document.write( "\"1%2Fb\" = \"3%2F2\" - \"23%2F24\"
\n" ); document.write( "\"1%2Fb\" = \"36%2F24\" - \"23%2F24\"
\n" ); document.write( "\"1%2Fb\" = \"13%2F24\"
\n" ); document.write( "cross multiply
\n" ); document.write( "13b = 24
\n" ); document.write( "b = \"24%2F13\"
\n" ); document.write( ":
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\n" ); document.write( "Check this in the 2nd original equation
\n" ); document.write( "\"23%2F24\" - \"13%2F24\" = \"10%2F24\" = \"5%2F12\"\r
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