document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581792>Question 581792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A lot of portable radios contain 15 good radios and 3 defective ones. If two are selected and tested, find the probability that at least one will be defective. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371809 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371809\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A lot of portable radios contain 15 good radios and 3 defective ones. If two are selected and tested, find the probability that at least one will be defective.<BR>\n" );
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document.write( "Binomial with p(defective) = 3/18 and p(good) = 15/18<BR>\n" );
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document.write( "P(>= 1 defective) = 1 - P(none defective)<BR>\n" );
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document.write( "= 1 - (15/18)^2<BR>\n" );
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document.write( "= 0.3056<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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