document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581680>Question 581680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe need 3 days to tile a rectangular pool of even depth. How long will it take him working at the same rate to tile a pool twice as long,twice as wide and twice as deep. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371779 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joe need 3 days to tile a rectangular pool of even depth. How long will it take him working at the same rate to tile a pool twice as long,twice as wide and twice as deep.<BR>\n" );
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document.write( "Let original surface area be LW + 2WH + 2LH<BR>\n" );
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document.write( "New surface area will be (2L)(2W) + 2(2W)(2H) + 2(2L)(2H)<BR>\n" );
document.write( "= 4LW + 8WH + 8LH = 4[LW + 2WH + 2LH) <BR>\n" );
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document.write( "Original time to tile = 3 days<BR>\n" );
document.write( "New time to tile = 4*3 = 12 days.<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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