document.write( "Question 581656: Find the equation of the circle passing through the origin and with the center (3,5)\r
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\n" ); document.write( "\n" ); document.write( "The answer should be written in the form (x-h) squared + (y-h)squared = radius squared\r
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Algebra.Com's Answer #371759 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Note: the origin is the point (0,0)\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" Start with the general equation of a circle.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-0%29%5E2%2B%28y-0%29%5E2=r%5E2\" Plug in \"h=0\" and \"k=0\" (since the center is the point (h,k) ).\r
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\n" ); document.write( "\n" ); document.write( "\"%283-0%29%5E2%2B%285-0%29%5E2=r%5E2\" Plug in \"x=3\" and \"y=5\" (this is the point that lies on the circle, which is in the form (x,y) ).\r
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\n" ); document.write( "\n" ); document.write( "\"%283%29%5E2%2B%285%29%5E2=r%5E2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"9%2B25=r%5E2\" Square each term.\r
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\n" ); document.write( "\n" ); document.write( "\"34=r%5E2\" Add.\r
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\n" ); document.write( "\n" ); document.write( "So because \"h=0\", \"k=0\", and \"r%5E2=34\", this means that the equation of the circle with center (0,0) that goes through the point (3,5) is \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-0%29%5E2%2B%28y-0%29%5E2=34\".\r
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\n" ); document.write( "\n" ); document.write( "which simplifies to \"x%5E2%2By%5E2=34\".\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x%5E2%2By%5E2=34\"
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