document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581399>Question 581399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve log4(9z+5)-log4(2z+2)=1? I've went over all of my lessons but I still don't understand it. Please show all work so I understand how to do it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371700 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you solve log4(9z+5)-log4(2z+2)=1? I've went over all of my lessons but I still don't understand it. Please show all work so I understand how to do it.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "log4(9z+5)-log4(2z+2)=1<BR>\n" );
document.write( "use division rule for logs<BR>\n" );
document.write( "log4[(9z+5)/2z+2)]=1<BR>\n" );
document.write( "convert to exponential form: base(4) raised to log of the number(1)=number(9z+5)/2z+2)<BR>\n" );
document.write( "4^1=(9z+5)/2z+2)<BR>\n" );
document.write( "4=(9z+5)/2z+2)<BR>\n" );
document.write( "9z+5=8z+8<BR>\n" );
document.write( "z=3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );