document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581543>Question 581543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is constructed. The length of this rectangle is double the width. Then a new rectangle is made by increasing each side by 3 meters. The perimeter of the new rectangle is 2 meters greater than four tiimes the length of the old rectangle. Find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371697 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Old rectangle:\r<BR>\n" );
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document.write( "L = 2W \r<BR>\n" );
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document.write( "New rectangle:\r<BR>\n" );
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document.write( "L+3, W+3\r<BR>\n" );
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document.write( "Perimter:\r<BR>\n" );
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document.write( "P = 2(L+W) = 2(2W+3 + W+3) = 4(2W) + 2\r<BR>\n" );
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document.write( "2(3W+6) = 8W + 2\r<BR>\n" );
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document.write( "6W + 12 = 8W + 2\r<BR>\n" );
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document.write( "2W = 10\r<BR>\n" );
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document.write( "W = 5\r<BR>\n" );
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document.write( "original dimensions:  10 x 5\r<BR>\n" );
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document.write( "CHECK:\r<BR>\n" );
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document.write( "Old rectangle: 10 x 5<BR>\n" );
document.write( "New rectangle: 13 x 8\r<BR>\n" );
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document.write( "P(new) = 2(21) = 42 = 4(10) + 2 &#8730; </SPAN>\n" );
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