document.write( "Question 581505: The radiator contains 12 gal of h2o.we draw off 3 gal and replace it w/ alcohol,then draw off 3 gal of mixture and replace w/ alcohol.etc, until 8 drawings and replacement made. How much alcohol is the final mixture? \n" ); document.write( "
Algebra.Com's Answer #371693 by scott8148(6628)\"\" \"About 
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each successive mixture has 3/4 (9/12) the amount of water (H2O) as the previous mixture\r
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\n" ); document.write( "\n" ); document.write( "the H2O in the final mixture is ___ 12 * (3/4)^8\r
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\n" ); document.write( "\n" ); document.write( "the amount of alcohol is 12 gal MINUS the amount of H2O
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