document.write( "Question 581415: Okay I'm stumped on this problem. I have tried to figure out the equation but I keep geting stuck. The problem is: \"A chemist has a 90% solution of sulfuric acid and a 70% solution of the same acid. How many gallons of each must be mixed in order to make 200 gallons of 75% solution?\"
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document.write( "Here's what I know: I know that x is the amount of the 90% solution and that y would be the amount of the 70% solution. I think that the equation would be .90x + .70y = .75 and that the other equation is x+y=200. but I am not sure I did that right and I keep getting fractions as my answer. Help please. \n" );
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Algebra.Com's Answer #371664 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Okay I'm stumped on this problem. I have tried to figure out the equation but I keep geting stuck. The problem is: \"A chemist has a 90% solution of sulfuric acid and a 70% solution of the same acid. How many gallons of each must be mixed in order to make 200 gallons of 75% solution?\" \n" ); document.write( "Here's what I know: I know that x is the amount of the 90% solution and that y would be the amount of the 70% solution. I think that the equation would be .90x + .70y = .75 and that the other equation is x+y=200. but I am not sure I did that right and I keep getting fractions as my answer. Help please. \n" ); document.write( ". \n" ); document.write( "You almost had it right. It should have been: \n" ); document.write( "Let x = amount (gallons) of 90% solution \n" ); document.write( "and y = amount (gallons) of 70% solution \n" ); document.write( ". \n" ); document.write( "x+y=200 (equation 1) \n" ); document.write( ".90x + .70y = .75(200) (equation 2) \n" ); document.write( ". \n" ); document.write( "Solving equation 1 for y \n" ); document.write( "x+y=200 \n" ); document.write( "y=200-x \n" ); document.write( "Substitute above into equation 2: \n" ); document.write( ".90x + .70y = .75(200) \n" ); document.write( ".90x + .70(200-x) = .75(200) \n" ); document.write( ".90x + 140-.70x = 150 \n" ); document.write( ".20x + 140 = 150 \n" ); document.write( ".20x = 10 \n" ); document.write( "x = 50 gallons (of 90% solution) \n" ); document.write( ". \n" ); document.write( "70% solution: \n" ); document.write( "x+y=200 \n" ); document.write( "50+y=200 \n" ); document.write( "y = 150 gallons\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |