document.write( "Question 581360: What is the focus of this parabola?\r
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document.write( "X^2 + 12X - 24Y + 84 = 0 \n" );
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Algebra.Com's Answer #371644 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the focus of this parabola? \n" ); document.write( "X^2 + 12X - 24Y + 84 = 0 \n" ); document.write( "complete the square \n" ); document.write( "(x^2+12x+36)-24y+84-36=0 \n" ); document.write( "(x+6)^2-24y+48=0 \n" ); document.write( "(x+6)^2=24y-48 \n" ); document.write( "(x+6)^2=24(y-2) \n" ); document.write( "This is an equation of a parabola which opens upwards of the standard form: (x-h)^2=4p(y-k), (h \n" ); document.write( "vertex: (-6,2) \n" ); document.write( "axis of symmetry: x=-6 \n" ); document.write( "4p=24 \n" ); document.write( "p=6 \n" ); document.write( "x-coordinate of focus=-6 \n" ); document.write( "y-coordinate of focus=8 (p units above the vertex on the axis of symmetry) \n" ); document.write( "focus: (-6,8) \n" ); document.write( " |