document.write( "Question 581139: Alexis can clean a gym in 5 hours. Isiah can clean a gym in 6 hours, and ray can do it in 10 hours. They plan to work together to get the job done quickly but Alexis and isiah show up a hour late. Is ray worked for a hour how much longer will it take them to clean the gym if they work together? \n" ); document.write( "

Algebra.Com's Answer #371625 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Alexis can clean a gym in 5 hours. Isiah can clean a gym in 6 hours, and ray can do it in 10 hours.
\n" ); document.write( "They plan to work together to get the job done quickly but Alexis and Isiah show up a hour late.
\n" ); document.write( " If ray worked for a hour how much longer will it take them to clean the gym if they work together?
\n" ); document.write( ":
\n" ); document.write( "Let t = time required after A & I show up
\n" ); document.write( "Let the completed job = 1 (a clean gym)
\n" ); document.write( ":
\n" ); document.write( " $\"%28%28t%2B1%29%29%2F10\"$ + $\"t%2F5\"$ + $\"t%2F6\"$ = 1
\n" ); document.write( "multiply by 30 to get rid of the denominators, results:
\n" ); document.write( "3(t+1) + 6t + 5t = 30
\n" ); document.write( "3t + 3 + 6t + 5t = 30
\n" ); document.write( "14t = 30 - 3
\n" ); document.write( "14t = 27
\n" ); document.write( "t = 27/14
\n" ); document.write( "t = 1.93 hrs after A & I show up \n" ); document.write( "

\n" );