document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581183>Question 581183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> semi-circular lawns are attached to both edges along the breadth of a rectangular lawn measouring 56m by 35m. find the total area enclosed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371608 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> semi-circular lawns are attached to both edges along the breadth of a rectangular lawn measuring 56m by 35m.<BR>\n" );
document.write( " find the total area enclosed<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The radius of the semi-circles: 35/2 = 17.5 m<BR>\n" );
document.write( "A = (56*35) + [<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A17.5%5E2 ALIGN=MIDDLE  ALT=\"pi%2A17.5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >]<BR>\n" );
document.write( "A = 1960 + 692.1<BR>\n" );
document.write( "A = 2922.1 sq/m </SPAN>\n" );
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