document.write( "Question 581316: How many liters of a 50% acid solution must be mixed with a 10% acid solution to get 360 L of a 40% acid solution? \n" ); document.write( "
Algebra.Com's Answer #371604 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Acid percent ---------------- quantity \n" ); document.write( "Type I 50.00% ---------------- x liters \n" ); document.write( "Type II 10.00% ------ 360 - x liters \n" ); document.write( "Mixture 40.00% ---------------- 360 \n" ); document.write( " \n" ); document.write( "50.00%x +10.00%(360-x)= 40.00% *360 \n" ); document.write( "50x+10(360-x)=14400 \n" ); document.write( "50x+3600-10x=14400 \n" ); document.write( "50x-10x =14400-3600 \n" ); document.write( "40x= 10800 \n" ); document.write( "/ 40 \n" ); document.write( "x=270 liters 50.00% \n" ); document.write( "90 liters 10.00% \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |