document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581366>Question 581366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)  A circular flower garden has a diameter of 10 feet.  One cubic yard of concrete is to be used to create a circular border of uniform width around the garden.  The border is to have a depth of 3 inches.  How wid will the border be?\r<BR>\n" );
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document.write( "2)  An open box is to be made from a rectangular piece of tin whose length is twice its width.  The box will be made by cutting a square of side 1 foot from each corner and folding up the edges.  If the box needs to hold 4 cubic feet, what are the dimensions of the piece of tin? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371601 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Radius of garden = 5ft\r<BR>\n" );
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document.write( "Area of garden = pi*r^2\r<BR>\n" );
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document.write( "Area = 25pi\r<BR>\n" );
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document.write( "Let the uniform width be x\r<BR>\n" );
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document.write( "radius = (5+x)\r<BR>\n" );
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document.write( "Area of this circle = pi*(5+x)^2\r<BR>\n" );
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document.write( "Area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285%2Bx%29%5E2%2Api ALIGN=MIDDLE  ALT=\"%285%2Bx%29%5E2%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Area of the concrete portion = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B5%29%5E2%2Api-x%5E2%2Api ALIGN=MIDDLE  ALT=\"%28x%2B5%29%5E2%2Api-x%5E2%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Area = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%5E2%2B10x%2B25%29%2Api-x%5E2%2Api ALIGN=MIDDLE  ALT=\"%28x%5E2%2B10x%2B25%29%2Api-x%5E2%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "simplify\r<BR>\n" );
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document.write( "Area = (10x+25)*pi\r<BR>\n" );
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document.write( "Volume of the concrete portion = (10x+25)*pi*1/4 cu. ft\r<BR>\n" );
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document.write( "Quantity of concrete required = 1 cu.yard = 27cu.ft\r<BR>\n" );
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document.write( "(10x+25)*pi *1/3 = 27\r<BR>\n" );
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document.write( "10x+25 = (3*27)/(3.14)\r<BR>\n" );
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document.write( "10x+25 = 25.8<BR>\n" );
document.write( "10x= 25.8-25<BR>\n" );
document.write( "10x= 0.8<BR>\n" );
document.write( "x= 0.8/10<BR>\n" );
document.write( "x= 0.08 feet<BR>\n" );
document.write( "x=0.96 in  the width\r<BR>\n" );
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document.write( "---\r<BR>\n" );
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document.write( "let the width be x <BR>\n" );
document.write( "length = 2x feet\r<BR>\n" );
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document.write( "1 foot square cut off from corners<BR>\n" );
document.write( "reduced length & width will be<BR>\n" );
document.write( "x-2  width<BR>\n" );
document.write( "length = 2x-2\r<BR>\n" );
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document.write( "height will be 1 foot\r<BR>\n" );
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document.write( "Volume = L*W*H\r<BR>\n" );
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document.write( "(x-2)(2x-2)*1<BR>\n" );
document.write( "2(x-2)^2=4\r<BR>\n" );
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document.write( "(x-2)^2=2<BR>\n" );
document.write( "take the square root\r<BR>\n" );
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document.write( "(x-2)= +/-sqrt(2)\r<BR>\n" );
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document.write( "x= 2+sqrt(2) Or 2-sqrt(2)\r<BR>\n" );
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document.write( "The width = 2+2sqrt(2)= 2(1+sqrt(2))<BR>\n" );
document.write( "Length = 4(1+sqrt(2))\r<BR>\n" );
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document.write( " </SPAN>\n" );
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