document.write( "Question 6736: Can somebody show me how to find the coordinates of the vertex of the graph of\"+2%5E2-6x%2B2+\" ?
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Algebra.Com's Answer #3716 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
There are several ways to find the coordinates of the vertex of a parabola.\r
\n" ); document.write( "\n" ); document.write( "I'm assuming that there is a typographical error in your question.\r
\n" ); document.write( "\n" ); document.write( "You probably meant to type:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+x%5E2+-+6x+%2B+2\"\r
\n" ); document.write( "\n" ); document.write( "If not, your question is meaningless.\r
\n" ); document.write( "\n" ); document.write( "If this is the equation you intended, then read on.\r
\n" ); document.write( "\n" ); document.write( "1) You could graph the equation and find the location of the vertex of the parabola, or\r
\n" ); document.write( "\n" ); document.write( "2) You could put the equation into the form:
\n" ); document.write( "\"y+=+a%28x-h%29%5E2+%2B+k\"
\n" ); document.write( "and read the coordinates of the vertex from: (h, k)
\n" ); document.write( "This method requires that you perform an operation known as \"completing the square\".\r
\n" ); document.write( "\n" ); document.write( "3) You could put your equation into standard form \"ax%5E2+%2B+bx+%2B+c+=+0\". Then find the x-coordinate of the vertex which is located at -b/2a.
\n" ); document.write( "Then you could get the y-coordinate by substituting the x-value into the equation \"y+=+x%5E2+-+6x+%2B+2\" and solve for y.\r
\n" ); document.write( "\n" ); document.write( "Here's method 2.
\n" ); document.write( "Set you equation equal to zero.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+6x+%2B+2+=+0\" Subtract 2 from both sides.
\n" ); document.write( "\"x%5E2+-+6x+=+-2\" Add the square of half the x-coefficient (-3)^2 = 9 to both sides.
\n" ); document.write( "\"x%5E2+-+6x+%2B+9+=+7\" Factor the left side.
\n" ); document.write( "\"%28x+-+3%29%28x+-+3%29+=+7\" Add 7 to both sides.
\n" ); document.write( "\"%28x+-+3%29%5E2+-+7+=+0\" You now have the equation in the a(x-h)^2 + k form
\n" ); document.write( "\"%28x+-+h%29%5E2+%2B+k\" h = 3 and k = -7\r
\n" ); document.write( "\n" ); document.write( "The coordinates of the vertex are: (h, k) or (3, -7)\r
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