document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581242>Question 581242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A liquid fertilizer requires dilution before use. How much liquid fertilizer must be added to 600mL of water to make a 25% fertilizer solution?  Can you show the work please? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371542 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of liquid fertilizer that needs to be added<BR>\n" );
document.write( "Now we know that the amount of pure fertilizer that exists before the mixture takes place has to equal the amount of pure fertilizer that exists after the mixture takes place, sooooo:<BR>\n" );
document.write( "x=0.25(600+x)<BR>\n" );
document.write( "x=150+0.25x  subtract 0.25x from each side<BR>\n" );
document.write( "x-0.25x=150<BR>\n" );
document.write( "0.75x=150<BR>\n" );
document.write( "x=200 ml----amount of liquid fertilizer needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "200ml=0.25*800ml<BR>\n" );
document.write( "200ml=200ml\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor<BR>\n" );
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