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document.write( "How many liters of water must be mixed with 20 liters of a 90% alcohol mixture so that the alcohol content of the mixture is reduced to 50%?\r
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Algebra.Com's Answer #371480 by mananth(16946) You can put this solution on YOUR website! -------------- percent ---------------- Amount \n" ); document.write( "Alcohol 90 ---------------- 20 liters \n" ); document.write( "Water 0 ---------------- x liters \n" ); document.write( "Total 50 ---------------- 20 + x liters \n" ); document.write( " \n" ); document.write( "90*20+0 x=50(20 +x) \n" ); document.write( "1800+0x =1000+50x \n" ); document.write( "-50x=-1800+1000 \n" ); document.write( "-50x = -800 \n" ); document.write( "/ -50 \n" ); document.write( "x = 16 of liters Water \n" ); document.write( " \n" ); document.write( " |