document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581118>Question 581118</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains left a station at the same time and traveled in opposite directions. One train traveled for 144 minutes at a rate that was 5 kilometers per hour faster than the speed of the first train. The faster train went twice as far as the slower train. How far did each train travel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371466 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the speed of train A be x km/h<BR>\n" );
document.write( "Train B traveled at x+5 km/h\r<BR>\n" );
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document.write( "Train B traveled 144 minutes= 2.4 hours   (144/60)\r<BR>\n" );
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document.write( "Distance traveled by train B = (x+5)*2.4\r<BR>\n" );
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document.write( "Distance traveled by Train A = 2.4x\r<BR>\n" );
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document.write( "Distance traveled by train B = twice distance traveled by train A\r<BR>\n" );
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document.write( "2.4(x+5)= 2*2.4x\r<BR>\n" );
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document.write( "2.4x+12=4.8x\r<BR>\n" );
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document.write( "4.8x-2.4x=12<BR>\n" );
document.write( "2.4x=12<BR>\n" );
document.write( "x=12/2.4<BR>\n" );
document.write( "x=5\r<BR>\n" );
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document.write( "speed of Train A = 5km/h---------- distance traveled = 2.4*5 12 km<BR>\n" );
document.write( "speed of train B = 10km/h----------distance traveled = 10*2.4 = 24 km </SPAN>\n" );
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