document.write( "Question 581128: I need help setting up this Linear Equation: While on vacation, Kevin went for a swim in a nearby lake. Swimming against the current, it took him 8 minutes to swim 200 meters. Swimming back to shore with the current took half as long. Find Kevin's average swimming speed and the speed of the lake's current. \n" ); document.write( "
Algebra.Com's Answer #371461 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
swimming speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "againstcurrent x-y 8 minutes
\n" ); document.write( "with current x+y 4 minutes
\n" ); document.write( "
\n" ); document.write( "Distance = 200 m distance= 200
\n" ); document.write( "t=d/r against current
\n" ); document.write( "200.00 / ( x - y )= 8.00
\n" ); document.write( "
\n" ); document.write( "8.00 x -8.00 y = 200.00 ....................1
\n" ); document.write( "
\n" ); document.write( "200.00 / ( x + y )= 4.00
\n" ); document.write( "4.00 ( x + y ) = 200.00
\n" ); document.write( "4.00 x + 4.00 y = 200.00 ...............2
\n" ); document.write( "Multiply (1) by 1.00
\n" ); document.write( "Multiply (2) by 2.00
\n" ); document.write( "we get
\n" ); document.write( "8.00 x -8.00 y = 200.00
\n" ); document.write( "8.00 x + 8.00 y = 400.00
\n" ); document.write( "16.00 x = 600.00
\n" ); document.write( "/ 16.00
\n" ); document.write( "x = 37.5 Meters /minute
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "8 x -8 y = 200
\n" ); document.write( "300 -8 y = 200
\n" ); document.write( "-8 y = 200 -300
\n" ); document.write( "-8 y = -100
\n" ); document.write( " y = 12.5 Meters / minute
\n" ); document.write( " swimming speed 37.5 Meters /minute (0.63m/s)
\n" ); document.write( " current current 12.5 Meters /minute (0.21m/s)
\n" ); document.write( " \n" ); document.write( "
\n" );