document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=581128>Question 581128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help setting up this Linear Equation:   While on vacation, Kevin went for a swim in a nearby lake.  Swimming against the current, it took him 8 minutes to swim 200 meters.  Swimming back to shore with the current took half as long. Find Kevin's average swimming speed and the speed of the lake's current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371460 by </B><A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><B>dfrazzetto(283)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfrazzetto><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dfrazzetto><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  d=rt\r<BR>\n" );
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document.write( "200 = (r-c)8\r<BR>\n" );
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document.write( "200 = (r+c)4\r<BR>\n" );
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document.write( "r - c = 25\r<BR>\n" );
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document.write( "r + c = 50<BR>\n" );
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document.write( "2r = 75\r<BR>\n" );
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document.write( "r = 37.5\r<BR>\n" );
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document.write( "c = 12.5 m/min\r<BR>\n" );
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document.write( "average swimming speed = total distance / total time = 400/12 = 33 1/3 m/min </SPAN>\n" );
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