document.write( "Question 581080: I don't quite understand what the question is asking. Could you help me solve this problem?\r
\n" ); document.write( "\n" ); document.write( " Directions: Logical Reasoning - Consider the equations \"+ax%5E2+%2B+bx+%2B+c=0\" and use the quadratic formula to justify the statement.\r
\n" ); document.write( "\n" ); document.write( " If \"+b%5E2-4ac+\" is positive, then the equation has two solutions.
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Algebra.Com's Answer #371448 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The quadratic formula is:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "It applies to the general quadratic equation:
\n" ); document.write( "\"+ax%5E2+%2B+bx+%2B+c+=+0\"
\n" ); document.write( "You can see there is a \" +- \" before the
\n" ); document.write( "square root sign. That means there are 2 solutions:
\n" ); document.write( "\"x%5B1%5D+=+%28-b+%2B+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "and
\n" ); document.write( "\"x%5B2%5D+=+%28-b+-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "If the \"+sqrt%28+b%5E2-4%2Aa%2Ac+%29+\" term is zero,
\n" ); document.write( "then \"+x%5B1%5D+=+x%5B2%5D+\" and there is 1 solution
\n" ); document.write( "but if this term is positive, then \"+x%5B1%5D+\"
\n" ); document.write( "and \"+x%5B2%5D+\" are different and there will be 2 solutions
\n" ); document.write( "Hope this helps
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