document.write( "Question 54922: I have this problem that I desperately need help with. I am supposed tro use factoring on this but I'm having trouble with it. It goes:\r
\n" ); document.write( "\n" ); document.write( "Tropical Pools sells an aboveground model for \"p\" dollars each. The monthly revenue from the sale of this product is given by\r
\n" ); document.write( "\n" ); document.write( "R = -0.08p^2 + 300p\r
\n" ); document.write( "\n" ); document.write( "Revenue is the product of \"p\" and the demand (quantity sold).\r
\n" ); document.write( "\n" ); document.write( "a.) Factor out the price on the right-hand side of the formula\r
\n" ); document.write( "\n" ); document.write( "b.) What is an expression of the monthly demand?\r
\n" ); document.write( "\n" ); document.write( "c.) What is the monthly demand for this pool when the price is $3000?\r
\n" ); document.write( "\n" ); document.write( "d.) What is the approximate maimum revenue?\r
\n" ); document.write( "\n" ); document.write( "Can anyone help me out with this?\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #37143 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The monthly revenue from the sale of this product is given by
\n" ); document.write( "R = -0.08p^2 + 300p
\n" ); document.write( "Revenue is the product of \"p\" and the demand (quantity sold).
\n" ); document.write( "a.) Factor out the price on the right-hand side of the formula
\n" ); document.write( "R=p(-0.08p+300)
\n" ); document.write( "b.) What is an expression of the monthly demand?
\n" ); document.write( "D=-0.08p+300
\n" ); document.write( "c.) What is the monthly demand for this pool when the price is $3000?
\n" ); document.write( "D(3000)=-0.08(3000)+300
\n" ); document.write( "D(3000)=240+300=540
\n" ); document.write( "d.) What is the approximate maximum revenue?
\n" ); document.write( "Maximum at -b/2a where a=-0.08, b=300
\n" ); document.write( "Max at -300/(-0.16)= 1875
\n" ); document.write( "R(1875)= -0.08(1875)^2+300(1875)=$281,250 (Maximum Revenue)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );