document.write( "Question 580973: \n" ); document.write( "
Algebra.Com's Answer #371408 by fionahayes05(1)\"\" \"About 
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substitute for the first equation:
\n" ); document.write( "2(4y+1)-3y=12
\n" ); document.write( "foil
\n" ); document.write( "8y+2-3y=12
\n" ); document.write( "subtract -3y from 8y
\n" ); document.write( "5y+2=12
\n" ); document.write( "subtract 2 from both sides
\n" ); document.write( "5y=10
\n" ); document.write( "divide by 10 by 5
\n" ); document.write( "y=2\r
\n" ); document.write( "\n" ); document.write( "to solve for x, plug 2 into the next equation.\r
\n" ); document.write( "\n" ); document.write( "x=4y+1
\n" ); document.write( "x=4(2)+ 1
\n" ); document.write( "x= 9\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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