document.write( "Question 580860: jo can do a pice of work in 20days while paul can do it in 25days. they work for 5 days,then his brother backed out. how many days did jo work alone? \n" ); document.write( "

Algebra.Com's Answer #371402 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Jo can do a piece of work in 20 days while Paul can do it in 25 days.
\n" ); document.write( " they work for 5 days, then his brother backed out.
\n" ); document.write( " how many days did Jo work alone?
\n" ); document.write( ":
\n" ); document.write( "Let t = time worked alone by Jo
\n" ); document.write( ":
\n" ); document.write( "Let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( " $\"%28%28t%2B5%29%29%2F20\"$ + $\"5%2F25\"$ = 1
\n" ); document.write( "Multiply by 100 to clear the denominators, results:
\n" ); document.write( "5(t+5) + 4(5) = 100
\n" ); document.write( "5t + 25 + 20 = 100
\n" ); document.write( "5t = 100 - 45
\n" ); document.write( "5t = 55
\n" ); document.write( "t = 55/5
\n" ); document.write( "t = 11 days Jo worked alone \n" ); document.write( "

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