document.write( "Question 580885: I need to solve two different logarithmic equations.
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\n" ); document.write( "1) 2log10x=10 (the first 10 is the base ten)\r
\n" ); document.write( "\n" ); document.write( "2) 9 log 10 x-4 = 11 (the ten is also the base in this equation, and the x - 4 is the exponent)
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Algebra.Com's Answer #371385 by dfrazzetto(283)\"\" \"About 
You can put this solution on YOUR website!
If the base is ten, just write log, it's understood:\r
\n" ); document.write( "\n" ); document.write( "2logx = 10\r
\n" ); document.write( "\n" ); document.write( "log(x) = 5\r
\n" ); document.write( "\n" ); document.write( "10^5 = x \r
\n" ); document.write( "\n" ); document.write( "x = 100,000\r
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\n" ); document.write( "\n" ); document.write( "9*log(x-4) = 11\r
\n" ); document.write( "\n" ); document.write( "log(x-4) = 11/9\r
\n" ); document.write( "\n" ); document.write( "x-4 = 10^(11/9)\r
\n" ); document.write( "\n" ); document.write( "x = 10^(11/9) + 4\r
\n" ); document.write( "\n" ); document.write( "x = 16.68 + 4 = 20.68 \n" ); document.write( "

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