document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54956>Question 54956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me on this equation?\r<BR>\n" );
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document.write( "  I need to complete the order pair so that each is a solution for the given equation:\r<BR>\n" );
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document.write( "  3x + 4y = 12\r<BR>\n" );
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document.write( "  pair 1 is  (8/3,)<BR>\n" );
document.write( "  pair 2 is (0,)\r<BR>\n" );
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document.write( "  Thanks,<BR>\n" );
document.write( "  Sher </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37136 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + 4y = 12 <BR>\n" );
document.write( "If x=8/3, then 3*8/3+4y = 12<BR>\n" );
document.write( "8+4y=12<BR>\n" );
document.write( "4y=4<BR>\n" );
document.write( "y=1<BR>\n" );
document.write( "(8/3,1)\r<BR>\n" );
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document.write( "If x=0, then 3*0+4y=12<BR>\n" );
document.write( "4y=12<BR>\n" );
document.write( "y=3\r<BR>\n" );
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document.write( "(0,3) \r<BR>\n" );
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document.write( "R^2 at SCC<BR>\n" );
document.write( " </SPAN>\n" );
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