document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=580638>Question 580638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> im brandon, i need help with substitution. problem is x-2y+2=0 and 2x-3y-2=0. i dont understand this one. please help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371327 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-2y+2=0<BR>\n" );
document.write( "-2x-3y-2=0<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Solve for x in the 1st eqn<BR>\n" );
document.write( "x-2y+2 = 0<BR>\n" );
document.write( "x = 2y-2<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Sub that for x in the other eqn.<BR>\n" );
document.write( "-2x-3y-2=0<BR>\n" );
document.write( "-2(2y-2) - 3y - 2 = 0<BR>\n" );
document.write( "-4y+4 - 3y = 2<BR>\n" );
document.write( "-7y = -2<BR>\n" );
document.write( "y = 2/7<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "x = 2y-2<BR>\n" );
document.write( "x = 4/7-2<BR>\n" );
document.write( "x = -10/7<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );