document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=580604>Question 580604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is three times older than his son.  in twelve years, the man will be twice as old as his son. how old is the son now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371316 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Son's age	x												<BR>\n" );
document.write( "Father's age			3      	x									<BR>\n" );
document.write( "	12	years later											<BR>\n" );
document.write( "Son's age	x	+	12										<BR>\n" );
document.write( "Father's age		3    	x	+	12								<BR>\n" );
document.write( "Father's age	2      	times older											<BR>\n" );
document.write( "	3    	x	+	12	=	2    	(	x	+	12	)		<BR>\n" );
document.write( "	3    	x	+	12	=	2    	x	+	24				<BR>\n" );
document.write( "		1	x			=	24	-12					<BR>\n" );
document.write( "		x	=	12	Son's age								<BR>\n" );
document.write( "	3    	x=	36	years		Father's age			<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );