document.write( "Question 54955: Can someone help me on this equation?\r
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document.write( " I need to complete the ordered pair so that each is a solution for the given equation:\r
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document.write( " 3x + 4y = 12\r
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document.write( " pair 1 is= (,3/4)
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document.write( " pair 2 is= (,0)\r
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document.write( " Thanks,
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document.write( " Sher \n" );
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Algebra.Com's Answer #37131 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Hi Sher, \n" ); document.write( "3x + 4y = 12 \n" ); document.write( " pair 1 is= (,3/4) \n" ); document.write( " pair 2 is= (,0) \n" ); document.write( "First substitute 3/4 in for y and solve for x. \n" ); document.write( "3x+4(3/4)=12 \n" ); document.write( "3x+12/4=12 \n" ); document.write( "3x+3=12 \n" ); document.write( "3x+3-3=12-3 \n" ); document.write( "3x=9 \n" ); document.write( "3x/3=9/3 \n" ); document.write( "x=3 \n" ); document.write( "So the first ordered pair is(3, 3/4). \n" ); document.write( ": \n" ); document.write( "Second substitute 0 in for y and solve for x: \n" ); document.write( "3x+4(0)=12 \n" ); document.write( "3x+0=12 \n" ); document.write( "3x=12 \n" ); document.write( "3x/3=12/3 \n" ); document.write( "x=4 \n" ); document.write( "So the second ordered pair is (4,0) \n" ); document.write( "Happy Calculating, Sher!!! \n" ); document.write( " |