document.write( "Question 580623: How many different arrangements of the word “scissors” are there? \n" ); document.write( "
Algebra.Com's Answer #371302 by Edwin McCravy(20054)\"\" \"About 
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document.write( "The answer would be 8! if the s's were all distinguishable, e.g., of \r\n" );
document.write( "different colors.\r\n" );
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document.write( "Since they are not distinguishable, 8! counts each arrangement 4! times too \r\n" );
document.write( "many, because in each arrangement there are 4! ways the 4 s's could be arranged\r\n" );
document.write( "within that arrangement, if they were of different colors.  To eliminate\r\n" );
document.write( "duplications in this case when they are not distinguishable, we must divide the\r\n" );
document.write( "8! by 4!:\r\n" );
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document.write( "Answer:  \"8%21%2F4%21\" = \"%288%2A7%2A6%2A5%2A4%2A3%2A2%2A1%29%2F%284%2A3%2A2%2A1%29\" =  = 8·7·6·5 = 1680\r\n" );
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document.write( "Edwin
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