document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54912>Question 54912</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me on this?\r<BR>\n" );
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document.write( "  Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h.  An hour later, Phil leaves Los Angeles and travels toward San Francisco at 60 mi/h.  If the two cities are 380 miles apart, how many hours will it take for Ching to meet Phil?\r<BR>\n" );
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document.write( " Thanks,   Adriana </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #37130 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=37130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance = (rate)(time) [Use the formula for distance while traveling (d=rt)]<BR>\n" );
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document.write( "Ching's distance=rt=(50mph)(unknown time)<BR>\n" );
document.write( "Phil's distance=rt= 60mph)(unknown time - 1hour)<BR>\n" );
document.write( "Ching's distance (rt) + Phil's distance(rt) = 380<BR>\n" );
document.write( "So, 50t+60(t-1)=380<BR>\n" );
document.write( "50t+60t-60=380<BR>\n" );
document.write( "110t=60+380<BR>\n" );
document.write( "110t=440<BR>\n" );
document.write( "t=4 hours<BR>\n" );
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document.write( "Check by plugging all of the variables back into the original equation:<BR>\n" );
document.write( "50t+60(t-1)=380<BR>\n" );
document.write( "50(4)+60(4-1)=380<BR>\n" );
document.write( "200+180=380<BR>\n" );
document.write( "380=380 [Checks out] </SPAN>\n" );
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