document.write( "Question 54953: Speed: A boat travels 36 miles down a river in 3 hours. If it takes the boat 9 hours to travel the same distance going up the river, what is the speed of the boat? What is the speed of the current of the river? \n" ); document.write( "
Algebra.Com's Answer #37128 by rapaljer(4671)\"\" \"About 
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Let x = speed of the boat in still water
\n" ); document.write( "y = speed of the current of the river\r
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\n" ); document.write( "\n" ); document.write( "x+y = rate downstream
\n" ); document.write( "x-y = rate upstream\r
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\n" ); document.write( "\n" ); document.write( "Distance = Rate * Time, so
\n" ); document.write( "\"Rate+=+Distance%2FTime\"\r
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\n" ); document.write( "\n" ); document.write( "x+y=\"36%2F3\"=12 Downstream
\n" ); document.write( "x-y=\"36%2F9\"=4 Upstream\r
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\n" ); document.write( "\n" ); document.write( "Add these two equations together:
\n" ); document.write( "2x = 16, so x = 8 mph in still water\r
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\n" ); document.write( "\n" ); document.write( "x+y = 12, where x = 8, y = 4 mph current.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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