document.write( "Question 54953: Speed: A boat travels 36 miles down a river in 3 hours. If it takes the boat 9 hours to travel the same distance going up the river, what is the speed of the boat? What is the speed of the current of the river? \n" ); document.write( "
Algebra.Com's Answer #37128 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = speed of the boat in still water \n" ); document.write( "y = speed of the current of the river\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y = rate downstream \n" ); document.write( "x-y = rate upstream\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance = Rate * Time, so \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y= \n" ); document.write( "x-y= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add these two equations together: \n" ); document.write( "2x = 16, so x = 8 mph in still water\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y = 12, where x = 8, y = 4 mph current.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |