document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=580475>Question 580475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of a pure 100% acid must be added to 2 liters of a 10% acid solution in order to produce a 20% solution? How much 20% solution will there be? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371256 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371256\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ------------	percent	----------------	Amount								<BR>\n" );
document.write( "Acid type I	10	----------------			2	liters					<BR>\n" );
document.write( "Pure acid	100	----------------			x	liters					<BR>\n" );
document.write( "Total	20	----------------	2	+	x	liters					<BR>\n" );
document.write( "											<BR>\n" );
document.write( "10*2+100x=20(2	+x)<BR>\n" );
document.write( "20+100	x=40+20	x			<BR>\n" );
document.write( "100x-20	x	=-20+	40			<BR>\n" );
document.write( "80	x	=	20								<BR>\n" );
document.write( "/	80										<BR>\n" );
document.write( "x	=	0.25	of	liters	Pure acid						<BR>\n" );
document.write( "		0.25	of	liters	Acid type I						<BR>\n" );
document.write( "m.ananth@hotmail.ca											<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );