document.write( "Question 580159: Your fishing boat moves at 12 miles per hour relative to the surrounding water. You ride it from your house up the Mississippi River to a point that’s 16 miles distant, and then return to your house. The round trip takes 4 hours. The speed of the river is \n" ); document.write( "
Algebra.Com's Answer #371242 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Your fishing boat moves at 12 miles per hour relative to the surrounding water. \n" ); document.write( " You ride it from your house up the Mississippi River to a point that’s 16 miles distant, and then return to your house. \n" ); document.write( " The round trip takes 4 hours. The speed of the river is \n" ); document.write( ": \n" ); document.write( "Let c = the speed of the river \n" ); document.write( "then \n" ); document.write( "(12-c) = effective speed up-river \n" ); document.write( "and \n" ); document.write( "(12+c) = effective speed down river \n" ); document.write( ": \n" ); document.write( "write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Upriver time + downriver time = 4 hrs \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "multiply by (12-c)(12+c), gets rid of the denominators and we have: \n" ); document.write( "16(12+c) + 16(12-c) = 4(12+c)(12-c) \n" ); document.write( "; \n" ); document.write( "192 + 16c + 192 - 16c = 4(144-c^2) \n" ); document.write( ": \n" ); document.write( "384 = 576 - 4c^2 \n" ); document.write( ": \n" ); document.write( "4c^2 = 576 - 384 \n" ); document.write( "4c^2 = 192 \n" ); document.write( "c^2 = 192/4 \n" ); document.write( "c^2 = 48 \n" ); document.write( "c = \n" ); document.write( "c = 6.9282 ~ 6.9 mph is the speed of the river \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out \n" ); document.write( " \n" ); document.write( "3.137 + .847 = 3.984 ~ 4 hrs \n" ); document.write( " |