document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=580381>Question 580381</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits in a two-digit number is 7. The new number obtained when the digits are reversed is 27 less than the original number. Find the original number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371221 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371221\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the two digit number be xy			<BR>\n" );
document.write( "x in the ten's place & y in units place	\r<BR>\n" );
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document.write( "x+y=7........................(1)\r<BR>\n" );
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document.write( "10y+x= 10x+y-27\r<BR>\n" );
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document.write( "9y-9x=27	<BR>\n" );
document.write( "/9<BR>\n" );
document.write( "y-x=3........................(2)\r<BR>\n" );
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document.write( "Add (1) & (2) \r<BR>\n" );
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document.write( "2y= 7+3<BR>\n" );
document.write( "2y=10<BR>\n" );
document.write( "y=5\r<BR>\n" );
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document.write( "x+y =7<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "so x= 2\r<BR>\n" );
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document.write( "The number is 25<BR>\n" );
document.write( " </SPAN>\n" );
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