document.write( "Question 580208: 50x-40y=200 \n" ); document.write( "
Algebra.Com's Answer #371163 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you want to solve for y.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"50x-40y=200\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-40y=200-50x\" Subtract \"50x\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-40y=-50x%2B200\" Rearrange the terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28-50x%2B200%29%2F%28-40%29\" Divide both sides by \"-40\" to isolate y.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28%28-50%29%2F%28-40%29%29x%2B%28200%29%2F%28-40%29\" Break up the fraction.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%285%2F4%29x-5\" Reduce.
\n" ); document.write( "
\n" );