document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=579946>Question 579946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 35 pounds of feed worth $0.36 per pound by mixing one kind worth $0.18 per pound with another worth $0.53 per pound. How many pounds of the cheaper kind should they use in the mix?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #371110 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=371110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $		----------------			quantity								<BR>\n" );
document.write( "Type I	0.18	----------------			x	pounds							<BR>\n" );
document.write( "Type II	0.53	------	35	-	x	pounds							<BR>\n" );
document.write( "Mixture	0.36	----------------	35										<BR>\n" );
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document.write( "0.18x+0.53(35-x)=0.36*35	<BR>\n" );
document.write( "0.18x+0.53(35-x	)=12.6			<BR>\n" );
document.write( "0.18x+	18.55-0.53x=12.6			<BR>\n" );
document.write( "0.18x-0.53x=12.6--18.55			<BR>\n" );
document.write( "-0.35	x			=	-5.95								<BR>\n" );
document.write( "/	-0.35												<BR>\n" );
document.write( "x=17	pounds$	0.18		Type I	<BR>\n" );
document.write( "18	pounds$	0.53		Type II	<BR>\n" );
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document.write( "m.ananth@hotmail.ca													<BR>\n" );
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